Friday, June 10, 2011

Duston's Solution

For my area maximization problem I measured the one end of the computer power cord and I found the length to be 5ft, so what i did was I entered that into excel and I found the length to be 1.25 and the width to be 1.25 also. My total area came out to be 1.5625 SQ. FT.

Thursday, June 9, 2011




I messured my headphones which had a length of 3 feet. The maximum area I could get with this length was 0.5625 square feet with a length and width of 0.75 feet.

Fencing



I used my IPod cord witch was 3 feet long when I used the spreadsheet my width was 0.75 and the length was o.75 as well. The maximum area is 0.5625 Square feet

Fencing Problem - Brittany's solution

I measured the internet connection cord. It was about 60 cm long. The maximum area is 225 cm. Each side of the perimeter fencing will be 15 cm.

Wednesday, June 8, 2011

Quon's Fencing

i used the mouse cord for my project and i measured it to about 57 inches the maximum area 203.0625 the width is 14.25 inches and the length is 14.25 inches

Tuesday, June 7, 2011

Fencing Question

I used the formula for area when I measured my head phones I got 35 cm of cord. So I took the formula y=((35-2x)/2)*x and plugged that into graph matica. When I found the vertex I got a width of 8.75 and a area of 76.56. The width and lengh are exactly the same too.

Solution to Maximization Problem

I used my keychain which is 20 cm in length. My width was 5.30 and my area was 25.

Colette's Solution










I measured my key chain it was around 2 feet so i rounded it to 2. My best solution to maximize the perimeter was 0.5 in width & 0.5 in length which it maximized to 0.25ft squared.

Monday, June 6, 2011

Hey so I have completed my assignment on "fencing" and this is what I have come up with.
By using the cord on the mouse I measured 5 feet. By using graphmatica and the formula my solution is 1.25 feet.

Maximizing Area Using a Quadratic Function













Accelerated Math ends on June 22,2011, this will be the last day you have to finish up any accelerated math.














At 36 1/2 minutes into the recording, there is very important information














Tuesday, May 31, 2011

Quadratic Functions

Today we talked about quadratic functions. We were told to find the definitions of the words, x-intercept, root of a quadratic function, solution of a quadratic, zero of a quadratic, and axis of symmetry of a quadratic.



Thursday, May 12, 2011




















































Today we are looking at the Exercise 5: Linear Programming Problems hand out. Mr.Maks went through the question 1 and Mr. Maks helped us step up question 4 for us to try ourselves. We are to try any 2 of the questions from page D-10, which is questions 5-12. Mr.Maks will go through them in the next couple of days and sometime next week we will probably have a quiz on solving Linear Programming Problems

Wednesday, May 4, 2011

Linear Programming

Linear Programming

Today we have learned how to solve Linear inequalities on Graphmatica. These are the intructions we did in  class...








I personally learned the ways of entering and calculating the problems in Graphmatica.
Theron Matthews

Thursday, April 28, 2011

Linear Equality






























Today we learned how to "cheat" and make a visual for our equations using Graphmatica.



Tuesday, April 19, 2011

Quiz Answers

Today we corrected the Quiz from the other day. We will be having another Quiz tomorrow which will be for marks. The reason we went over the quiz was to make sure that we know how to do it for the quiz tomorrow.























Friday, April 15, 2011

Who did Better

Who did better is asked a lot in classes when we get a test. Today we were shown how to really know who did better using z - scores I will put the lesson on to tis post for anyone who needs it.





Wednesday, April 13, 2011

invNORM




Today Mr.M is showing how to use invNORM. The whole point of this lesson is to give us the percentage of peolple the police academy will reject applications from. It turns out that anyone shorter than 65.44" can't be a police officer. The formula Mr.M used to get this answer is invNORM (0.15, mean, standard deviation) the 0.15 is the percentage of people who are excluded from the police department(100-85=15) Mr.M also wanted us to assume the mean in 67' and the standard deviation is 1.5', find the "cut-off" height? It is lower than 65.5 that is where the bottom 15 percent is on the chart.


I would like to do my report on teen drinking.